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Ashiqe on orkut
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    5 starsShuvo | Shared With: Everyone - Jan 30 2009 | my, netvibes, orkut
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  • jamil
    Jul 25 2008

    Usando polinĂ´mio de Vandermond,MOD e modular
    f(n) = [x(x+1)(x-1)(x+2)(x-2)(x+3)/3(3+1)(3-1)(3+2)(3-2)(3+3)].......+

    +[x(x-1)(x+1)(x+2)(x-3)(x+3)/2(2-1)(2+1)(2+2)(2-3)(2+3)]...............+

    +[x(x-1)(x-2)(x+2)(x-3)(x+3)/-1(-1-1)(-1-2)(-1+2)(-1-3)(-1+3)]..........+

    +[x(x-1)(x+1)(x-2)(x-3)(x+3)/-2(-2-1)(-2+1)(-2-2)(-2-3)(-2+3)].

    para n, z e x inteiros tal que n= 4z+x e |x|<4

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